consecutive even positive integers
Smaller integer = x
Larger integer = x+2
both of which is greater than 5
x > 5, and since it is an integer, x ≧ 6
 their sum is less than 23
x + (x+2) < 23
x + x + 2 < 23
   2x + 2 < 23
       2x < 21
        x < 10.5
        x ≦ 10
x ≧ 6 is the same 6 ≦ x so we are to use 
integers in this interval
6 ≦ x ≦ 10
 x   x+2
 6    8
 8   10
10   12
Edwin