SOLUTION: Find four consecutive integers such that the sum of the two largest subtracted from twice the sum of the two smallest is 15.

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Question 703801: Find four consecutive integers such that the sum of the two largest subtracted from twice the sum of the two smallest is 15.
Answer by josgarithmetic(39617) About Me  (Show Source):
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Four consecutive integers: n, n+1, n+2, n+3.

Find four consecutive integers such that

the sum of the two largest (n+2+n+3), subtracted from (-(n+2+n+3)), twice the sum of the two smallest (2*(n+n+1)), is 15.

2%28n%2B%28n%2B1%29%29-%28%28n%2B2%29%2B%28n%2B3%29%29=15
Solve for n, find the other three integers.
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Answer: 9, 10, 11, 12