Question 700129: Find three consecutive even integers such that twice the sum of the first and third integers is twenty-one more than the second integer Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let the consecutive even integers = , , and
given:
This didn't work because I', going to get
5,7, and 9 which are odd numbers.
I need to call the smallest number to make sure it will be even
My number are , ,
given:
This didn't work either.
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Now that I think about it, the problem has no solution.
It is saying that twice the sum of 2 numbers ( which is even ) is
equal to 21 plus an even number ( which is odd ), and
even cannot equal odd.
