SOLUTION: find three consecutive odd integers such that the largest decreased by three times the second is 47 less than the smallest

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Question 698284: find three consecutive odd integers such that the largest decreased by three times the second is 47 less than the smallest
Answer by neatmath(302) About Me  (Show Source):
You can put this solution on YOUR website!

Let x be your first unknown integer.

Then the other two integers will be x%2B2 and x%2B4

Then we have:

%28x%2B4%29-3%2A%28x%2B2%29=x-47

x%2B4-3x-6=x-47

-2x-2=x-47

-2=3x-47

45=3x

x=15

Thus the three integers are 15, 17, and 19.

Double check this, and it should work.

I hope this helps! Keep practicing! :)

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