SOLUTION: Find three consecutive even integers such that twice the smallest number is twelve more than the largest number?
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Question 693152
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Find three consecutive even integers such that twice the smallest number is twelve more than the largest number?
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
2(x-2) = 12 + (x+2)
2x - 4 = x + 14
x = 18
integers: 16, 18, 20
