SOLUTION: Given three consecutive odd numbers such that the square of the second number is 192 less than the square of the third. Find those numbers.

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Question 634306: Given three consecutive odd numbers such that the square of the second number is 192 less than the square of the third. Find those numbers.
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the odd numbers be n, n+2, n+4
(n+2)^2=(n+4)^2-192
n^2+4n+4=n^2+8n+16-192
4n-8n=16-192-4
-4n= 180
/4
n=45
45,47 & 49

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive ODD numbers
2n-1, 2n+1, 2n+3

%282n%2B1%29%5E2=%282n%2B3%29%5E2-192

4n%5E2%2B4n%2B1=4n%5E2%2B12n%2B9-192
4n%2B1=12n-183
4n-12n=-184
8n=184
n=23

The odd numbers are 45, 47, 49