SOLUTION: the product of two consecutive odd integers is 77 more than twice the larger, Find the integers please. I cannot set up "product" consecutive integers?
Question 557158: the product of two consecutive odd integers is 77 more than twice the larger, Find the integers please. I cannot set up "product" consecutive integers? Found 3 solutions by Alan3354, stanbon, laurien56:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! the product of two consecutive odd integers is 77 more than twice the larger, Find the integers please. I cannot set up "product" consecutive integers?
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The product is x*(x+2)
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x*(x+2) = 2(x+2) + 77
x^2 + 2x = 2x + 4 + 77
x^2 - 81 = 0
x = ± 9
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--> 9 & 11
and -9 & -7
You can put this solution on YOUR website! product of two consecutive odd integers is 77 more than twice the larger,
Find the integers.
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Equation:
x(x+1) = 2(x+1)+77
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x^2+x = 2x+79
x^2-x-79 = 0
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This quadratic does not have an integer solution.
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Cheers,
Stan H.
You can put this solution on YOUR website! Geez Stan I came up with 9 and 11 because I did x(x+2) because they are two consecutive odd integers. Is that right?
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