SOLUTION: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third.      Log On


   

Question 556089: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third.
Answer by TutorDelphia(193) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive integers. If we say the first one is n, than the 3 will be n, n+1 and n+2
Therefore we can write the problem as
n*(n+1)=-6*(n+2)
Distribute the n and -6
n%5E2%2Bn=-6n-12
Add 6n to both sides
n%5E2%2B7n=-12
add 12 to both sides
n%5E2%2B7n%2B12=0
factor
(n+3)(n+4)=0
n=-3 or -4
So our integers would be -3,-2,-1
or -4,-3,-2
-3*-2=-1*6
6=6
-4*-3=-2*-6
12=12