Question 551548: Find four consecutive positive integers such that the product of the first and the fourth is four less than twice the first multiplied by the fourth
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the integers be x, x+1, x+2, x+3
x(x+3)=2x(x+3)-4
x^2+3x=2x^2+6x-4
x^2+3x-4=0
x^2+4x-x-4=0
x(x+4)-1(x+4)=0
(x+4)(x-1)=0
x=1 which is positive
1,2,3,4
|
|
|