Question 551268: three consecutive intergers such that the product of the first is 2 more than 9 times the third: need to show work also....... Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! three consecutive intergers such that the product of the first is 2 more than 9 times the third
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Integers are n, n+1 & n+2
n*(n+1) = 9(n+2) + 2
Can you finish it?