SOLUTION: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width. I tried these 2 formulas: L= 5W-20

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width. I tried these 2 formulas: L= 5W-20      Log On


   



Question 549895: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width.
I tried these 2 formulas:
L= 5W-20
L x W = 60
Can they work?

Answer by asuar010(338) About Me  (Show Source):
You can put this solution on YOUR website!
yes, substitute L in the multiplication part and solve for W, then substitute and solve for L.