SOLUTION: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width.
I tried these 2 formulas:
L= 5W-20
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width.
I tried these 2 formulas:
L= 5W-20
Log On
Question 549895: The length of a rectangle is 20 centimeters less than five times its width. If the area is 60 square centimeters, find the length and width.
I tried these 2 formulas:
L= 5W-20
L x W = 60
Can they work? Answer by asuar010(338) (Show Source):
You can put this solution on YOUR website! yes, substitute L in the multiplication part and solve for W, then substitute and solve for L.