SOLUTION: please help me solve this equation: find two consecutive integers such that 8 times the first equals 2 less than 5 times the second

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Question 549031: please help me solve this equation: find two consecutive integers such that 8 times the first equals 2 less than 5 times the second
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call n our smaller number, then the next consecutive number is n+1
Using the question we can make some equations:
8n=5%28n%2B1%29-2
And solve for n
8n=5n%2B5-2
8n=5n%2B3
8n-5n=5n%2B3-5n
3n=3
n=3%2F3
n=1
So the two consecutive numbers are 1 and 2