SOLUTION: the squares of two consecutive integers differ by 95. find the integers

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Question 547653: the squares of two consecutive integers differ by 95. find the integers
Answer by Maths68(1474) About Me  (Show Source):
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Let
First integer = x+1
Second integer = x+2

The squares of two consecutive integers differ by 95.
%28x%2B2%29%5E2-%28x%2B1%29%5E2=95
%28x%2B2%29%5E2-%28x%2B1%29%5E2=95
x%5E2%2B4x%2B4-x%5E2-2x-1=95
cross%28x%5E2%29%2B4x%2B4-cross%28x%5E2%29-2x-1=95
4x%2B4-2x-1=95
2x%2B3=95
2x=95-3
2x=92
2x%2F2=92%2F2
x=46


First integer = x+1=46+1=47
Second integer = x+2=46+2=48