SOLUTION: Find two consecutive integers such that the product of the two integers is 12 more than the square of the smaller integer?
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Question 544819
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Find two consecutive integers such that the product of the two integers is 12 more than the square of the smaller integer?
Answer by
mananth(16946)
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let the integers be x & x+1
x(x+1)=x^2-12
x^2+x=x^2-12
x=-12
The numbers are -12 & -13
