You can put this solution on YOUR website! The product of two consecutive even integers
is 6 more than three times their sum.
find the integers
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1st: 2x
2nd: 2x+2
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Equation:
(2x)(2x+2) = 3(2x + 2x+2) + 6
4x^2+4x = 3(4x+2) + 6
4x^2+4x = 12x + 12
4x^2 - 8x -12 = 0
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x^2 - 2x -3 = 3
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(x-3)(x+1) = 0
x = 3 or x = -1
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Positive solution:
1st 2*3 = 6
2nd: 2x+2 = 8
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Cheers,
Stan H.
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