SOLUTION: find two consecutive integers whose product is 7 more than the square of the smaller number

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Question 505978: find two consecutive integers whose product is 7 more than the square of the smaller number
Answer by Maths68(1474) About Me  (Show Source):
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Let
Smaller integer = x
Greater integer= x+1
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Given
x*(x+1)=x^2+7
x*(x+1)=x^2+7
x^2+x=x^2+7
x^2-x^2+x=7
x=7
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Smaller integer = x =7
Greater = x+1 = 7+1=8
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Check
8*7=7^2+7
56=49+7
56=56