SOLUTION: the sum of squares of two consecutive odd integers is 202 find the integers

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Question 469029: the sum of squares of two consecutive odd integers is 202 find the integers
Answer by mananth(16946) About Me  (Show Source):
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numbers are x& x+2
x%5E2%2B%28x%2B2%29%5E2=202
x%5E2%2Bx%5E2%2B4x%2B4=202
2x%5E2%2B4x-198=0
x%5E2%2B2x-99=0
x%5E2%2B11x-9x-99=0
x%28x%2B11%29-9%28x%2B11%29=0
(x-9)(x+11)=0
x=9 OR -11
The numbers
9 ,11
-11,-9