Find two natural numbers, the sum of whose squares is 25 times their sum and also equal to 50 times their difference
Let x be the larger and y be the smaller.
x² + y² = 25(x + y) = 50(x - y)
25(x + y) = 50(x - y)
Divide both sides by 25
x + y = 2(x - y)
x + y = 2x - 2y
3y = x
Substitute 3y for x in:
x² + y² = 25(x + y)
(3y)² + y² = 25(3y + y)
9y² + y² = 75y + 25y
10y² = 100y
y² = 10y
y² - 10y = 0
y(y - 10) = 0
y = 0, y - 10 = 0
y = 10
0 is not a natural number, so y = 10
and since
3y = x
3(10) = x
30 = x
So the two natural numbers are 30 and 10.
Checking:
The sum of their squares is 30²+10² = 900+100 = 1000
Their sum is 30+10 = 40
25 times 40 = 1000. That checks.
Their difference is 30-10 = 20
50 times 20 = 1000. That checks and
so the answers are indeed 30 and 10.
Edwin