SOLUTION: A poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the lengths of the sides of the poster and t

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: A poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the lengths of the sides of the poster and t      Log On


   

Question 451346: A poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the lengths of the sides of the poster and the sign.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
x2=(x-2)2+20
x2=x2-4x+4+20
4x=24
x=6
x-2=4
The sign is 6'x6';the poster is 4'x4'..