SOLUTION: 1. Find 3 consecutive integers such that twice the smallest is 8 more than the largest.

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Question 445432: 1. Find 3 consecutive integers such that twice the smallest is 8 more than the largest.
Answer by rwm(914) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+1, x+2
2x=(x+2)+8
2x=x+10
x=10
10,11,12
check
20=12+8
20=20
ok