SOLUTION: Find two consecutive odd integers such that the square of the first decreased by the second is 28. I just don't understand how to set it up and prove that it is right, my gues

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find two consecutive odd integers such that the square of the first decreased by the second is 28. I just don't understand how to set it up and prove that it is right, my gues      Log On


   

Question 432974: Find two consecutive odd integers such that the square of the first decreased by the second is 28.

I just don't understand how to set it up and prove that it is right, my guess is obvious 5, -3 Help
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x and (x+2)represent the two consecutive odd integers

Question states***

 x^2 - (x+2) = 28

 x^2 -x -30 = 0

factoring

(x-6)(x+5) = 0

(x-6)= 0    x = 6  |Toss out this solution as it is not an odd number

(x+5) =0    x = -5   the two consecutive odd integers are -5,-3

 

CHECKING our Answer***

  25 -(-3) = 28