SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer.      Log On


   

Question 397738: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2, x+4 be the integers, where x is even. Then,

%28x%2B2%29%28x%2B4%29+=+20+%2B+10x

x%5E2+%2B+6x+%2B+8+=+20+%2B+10x

x%5E2+-+4x+-+12+=+0

%28x-6%29%28x%2B2%29+=+0

x = 6, -2

Checking, both of these satisfy, but the question looks for positive even integers. So {6, 8, 10} are the three integers.