SOLUTION: What is the sum of two numbers that is -14, with their product at 48? I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48, -x^2 - 14x - 48 ?????

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: What is the sum of two numbers that is -14, with their product at 48? I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48, -x^2 - 14x - 48 ?????      Log On


   



Question 392675: What is the sum of two numbers that is -14, with their product at 48?
I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48,
-x^2 - 14x - 48 ?????

Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the sum of two numbers that is -14, with their product at 48?
The answer to your question is that it's an algebra problem.
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You should say "the sum of two numbers that is -14, with their product at 48?find the 2 numbers"
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I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48,
-x^2 - 14x - 48 ?
You had the right idea, but lost the equal sign.
-x^2 - 14x = 48 is better
x%5E2+%2B+14x+%2B+48+=+0
(x+6)(x+8) = 0
x = -6, -8
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And, yes, I can be pedantic.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
sum of two numbers that is -14
Let x and (-14 -x) represent tthe two numbers
Question states
x(-14-x) = 48
-14x - x^2 - 48 = 0 |good work to thus far!
x^2 +14x + 48 = 0
factoring
(x+6)(x+8)=0
(x+6)=0
x = -6 Numbers are -6,-8 (-14-(-6) = -8)
(x+8)=0
x = -8 yields the same results. Numbers are -8, -6