SOLUTION: Find three consecutive even integers such that 3 times the sum of the first two is 48 less than the third.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive even integers such that 3 times the sum of the first two is 48 less than the third.      Log On


   



Question 39176: Find three consecutive even integers such that 3 times the sum of the first two is 48 less than the third.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Sections:
x
x%2B2
x%2B4
Equation:
3%28x+%2B+%28x+%2B+2%29%29+=+%28x+%2B+4%29+-+48
3%282x+%2B+2%29+=+x+-+44
6x+%2B+6+=+x+-+44
5x+=+-50
x+=+-10
There are no solutions.