SOLUTION: find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94

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Question 352719: find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94
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The easy way:
The sum is aprox 6 times the 1st integer
94/6 = 15.xxx
--> 13, 15 & 17
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The hard way:
n, n+2 and n+4 are the integers
n + 2(n+2) + 3(n+4) = 94
6n + 16 = 94
6n = 78
n = 13