SOLUTION: A LOT IS IN THE SHAPE OF THE RIGHT TRIANGLE. THE SHORTER LEG MEASURES 180 METERS. THE HYPOTENUSE IS 60 METERS LONGER THAN THE LENGTH OF THE LONGER LEG. HOW LONG IS THE LONGER LEG?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: A LOT IS IN THE SHAPE OF THE RIGHT TRIANGLE. THE SHORTER LEG MEASURES 180 METERS. THE HYPOTENUSE IS 60 METERS LONGER THAN THE LENGTH OF THE LONGER LEG. HOW LONG IS THE LONGER LEG?       Log On


   

Question 351072: A LOT IS IN THE SHAPE OF THE RIGHT TRIANGLE. THE SHORTER LEG MEASURES 180 METERS. THE HYPOTENUSE IS 60 METERS LONGER THAN THE LENGTH OF THE LONGER LEG. HOW LONG IS THE LONGER LEG?
A)240m
B)300m
C)360m
D)180m
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A LOT IS IN THE SHAPE OF THE RIGHT TRIANGLE. THE SHORTER LEG MEASURES 180 METERS. THE HYPOTENUSE IS 60 METERS LONGER THAN THE LENGTH OF THE LONGER LEG. HOW LONG IS THE LONGER LEG?
A)240m
B)300m
C)360m
D)180m
.
Apply Pythagorean theorem:
Let x = length of longer leg
then
180 = shorter leg
60+x = hypotenuse
.
x^2 + 180^2 = (60+x)^2
x^2 + 180^2 = (60+x)(60+x)
x^2 + 32400 = 3600 + 120x + x^2
32400 = 3600 + 120x
32400 = 3600 + 120x
28800 = 120x
240 meters = x