SOLUTION: Find three consecutive integers such that the sum of the squares of the second and third exceeds twice the square of the first by 41.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive integers such that the sum of the squares of the second and third exceeds twice the square of the first by 41.      Log On


   

Question 338996: Find three consecutive integers such that the sum of the squares of the second and third exceeds twice the square of the first by 41.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be x, x+1 and x+2
(x+1)^2 + (x+2)^2 = 2x^2+41
x^2+2x+1+x^2+4x+4=2x^2+41
6x=36
x=6
.
Ed