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The largest of the 10 odd positive integers will as large
as possible if all the other 9 are as small as possible. So
if we make the other 9 odd integers all 1's, they will have
sum 9 and that will make the 10th integer have to be 22-9 or 13.
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 13 = 22
Edwin