SOLUTION: I am thinking of three consecutive negative numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers?
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Question 324848: I am thinking of three consecutive negative numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I am thinking of three consecutive negative numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers?
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1st: x-1
2nd: x
3rd: x+1
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Equation:
x(x-1)-3(x+1) = 57
x^2-x-3x-3 = 57
x^2-4x-60 = 0
(x-10)(x+6) = 0
Negative solution:
x = -6
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1st: x-1 = -7
2nd: x = -6
3rd: x+1 = -5
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Cheers,
Stan H.
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