SOLUTION: What are two consecutive odd integers, such that six times the larger minus two times the smaller is 152?

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Question 323156: What are two consecutive odd integers, such that six times the larger minus two times the smaller is 152?
Found 2 solutions by josmiceli, QH:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the consecutive odd integers n and n+%2B+2
given:
6%2A%28n+%2B+2%29+-+2n+=+152
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6n+%2B+12+-+2n+=+152
4n+=+152+-+12
4n+=+140
n+=+35
n+%2B+2+=+37
The integers are 35 and 37

Answer by QH(50) About Me  (Show Source):
You can put this solution on YOUR website!
Assign variables to your integers.
The first (or smaller) will be X
Because they are consecutive ODD integers you will add 2 to the first integer to find the second.
So the second (larger) will be X+2
"six times the larger minus two times the smaller is 152" translates to
6(x+2)-2x=152
now solve for x using order of operations
6x+12-2x=152
4x+12=152
4x=140
x=35 so 35 is your first, smaller integer.
x+2=37 so 37 is your second, larger integer.
*check*
six times the larger minus two times the smaller is 152
6(37)-2(35)=152
222-70=152
152=152