SOLUTION: Find three consecutive positive integers such that twice the product of the two smaller integers is 88 more than the product of the two larger integers.
Question 316961: Find three consecutive positive integers such that twice the product of the two smaller integers is 88 more than the product of the two larger integers. Answer by JBarnum(2146) (Show Source):
You can put this solution on YOUR website! x,x+2,x+4
x and x+2 are the 2 smaller numbers "twice the product of the two smaller integers is 88 more than the product of the two larger integers" add subtract
doesnt come out to a whole number so either thats suppose to be that way in the answer or the question was written wrong.
x= 10.8488578017961 or -8.8488578017961
(x+2)= 12.8488578017961 or -6.8488578017961
(x+4)= 14.8488578017961 or -4.8488578017961