SOLUTION: The length of a rectangle is 4 cm longer than the width. If the perimeter of the rectangle is 20 centimeters, what is the area of the rectangle?

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Question 315539: The length of a rectangle is 4 cm longer than the width. If the perimeter of the rectangle is 20 centimeters, what is the area of the rectangle?
Answer by moshiz08(60) About Me  (Show Source):
You can put this solution on YOUR website!
Length is 4 more than width, that is +L+=+4+%2B+W.
Perimeter is the sum of the four sides. Since we have a rectangle, opposite sides have the same length. So two of the sides have length L and the other two are the width W. So +P+=+2L+%2B+2W+.
We are given that P+=+20, so +P+=+20+=+2L+%2B+2W+. We can substitute our equation for L in here now:
20+=+2L+%2B+2W+=+2%284%2BW%29+%2B+2W+
Distribute the 2 to get
+20+=+8+%2B+2W+%2B+2W+
20+=+8+%2B+4W+
Subtract 8 from both sides to get
+12+=+4+W
Dividing by 4 gives
+3+=+W+
The width is 3. The length is 4 more than the width, which means the length is 7.
Thus, we have a 3 x 7 rectangle which has an area of 21 square centimeters.
We checked that the length of 7 is 4 more than the width 3. Now check to make sure that indeed the perimeter is 20, and then you have your answer.