SOLUTION: Please show work Two negative integers have a sum of -10. If the sum of their squares is 68, than what are the two integers?

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Question 309100: Please show work
Two negative integers have a sum of -10. If the sum of their squares is 68, than what are the two integers?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.A%2BB=-10
2.A%5E2%2BB%5E2=68
From eq. 1,
A=-10-B=-%28B%2B10%29
A%5E2=%28B%2B10%29%5E2
A%5E2=B%5E2%2B20B%2B100
Substitute into eq. 2,
A%5E2%2BB%5E2=68
B%5E2%2B20B%2B100%2BB%5E2=68
2B%5E2%2B20B%2B32=0
B%5E2%2B10B%2B16=0
%28B%2B2%29%28B%2B8%29=0
Two solutions:
B%2B2=0
B=-2
, then from eq. 1, +A=-8+
.
.
.
B%2B8=0
B=-8
, then from eq. 1, A=-2
.
.
.
-2 and -8 are your two integers.