Question 306431: For two consecutive integers, the sum of the smaller and twice the larger is 29. Find the smaller integer. Found 2 solutions by JBarnum, richwmiller:Answer by JBarnum(2146) (Show Source):
You can put this solution on YOUR website! You were close to the right topic.
n+2*(n+1)=29
Solve for n the smaller integer
3n+2=29
3n=27
n=9
n+1=10
check
9+20=29
ok