SOLUTION: find 3 consecutive integer that the product of the first is 23 more than the 3rd integer

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Question 295504: find 3 consecutive integer that the product of the first is 23 more than the 3rd integer
Answer by alicealc(293) About Me  (Show Source):
You can put this solution on YOUR website!
1st integer = x
2nd integer = x + 1
3rd integer = x + 2
x%2A%28x%2B1%29+=+%28x+%2B+2%29+%2B+23
x%5E2+%2B+x+=+x+%2B+25
x%5E2+%2B+x+-+x+-+25+=+0
x%5E2+-+25+=+0
%28x+-+5%29%2A%28x+%2B+5%29+=+0
x - 5 = 0 or x + 5 = 0
x = 5 or x = -5

so,there are 2 answers:
1st integer = x = 5
2nd integer = x + 1 = 5 + 1 = 6
3rd integer = x + 2 = 5 + 2 = 7
or
1st integer = x = -5
2nd integer = x + 1 = -5 + 1 = -4
3rd integer = x + 2 = -5 + 2 = -3