SOLUTION: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.      Log On


   

Question 288967: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Here are the 4 consecutive even integers:
x
x + 2
x + 4
x + 6
Here is the equation you need to solve this problem:
x^2 + (x + 2)^2 = (x + 6) + 12