SOLUTION: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8.

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Question 262218: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2, x+4 be our 3 consecutive odd integers.
from above, we get
x%2A%28x%2B2%29+=+x%2B4+%2B+8
distributing the left we get
x%5E2+%2B+2x+=+x+%2B+4+%2B+8
simplifying the right we get
x%5E2+%2B+2x+=+x+%2B+12
setting the equation = 0, we get
x%5E2+%2B+x+-+12+=+0
factoring we get
%28x%2B4%29%28x-3%29+=+0+
solving each for x we get
x+=+-4 - which we can't use
and
x+=+3
this means we have
{3, 5, 7}