SOLUTION: The product of three consecutive integers is 2184 . What is the sum of the integers ? (A)34 (B) 33 (C) 36 (D) 39 (E) none of these

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The product of three consecutive integers is 2184 . What is the sum of the integers ? (A)34 (B) 33 (C) 36 (D) 39 (E) none of these       Log On


   



Question 249142: The product of three consecutive integers is 2184 . What is the sum of the integers ?
(A)34 (B) 33 (C) 36 (D) 39 (E) none of these

Answer by chosenpoint(26) About Me  (Show Source):
You can put this solution on YOUR website!
A standard word problem involving consecutive integers.

Easy Trial and Error Solution (which would be the way to go on a test, scroll down for the hard solution!):

Now, since we are given possible choices, we can just try trial and error to solve this problem and skip the entire cubic equation we will see in the hard solution below this one.

For example, I can just try different numbers on my calculator to see what I come up with. I know that 10*10*10 is 1000, so I will start with 10 as my first integer:

10*11*12=1320 nope, too low so I will go to 11

11*12*13=1716 again, too low, so I will go to 12

12*13*14=2184 bingo!

then to get the answer, I just add the three integers together

12+13+14=39 final answer D

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Alternative Hard Mathematical Solution (scroll up for the easy solution!):

Let x be the first integer.

Then the three integers are:

x, x+1, and x+2

To solve, we just use the given info about their products:

x%2A%28x%2B1%29%2A%28x%2B2%29=2184 given

x%2A%28x%5E2%2Bx%2B2x%2B2%29=2184 distributing

x%2A%28x%5E2%2B3x%2B2%29=2184 simplifying

x%5E3%2B3x%5E2%2B2x=2184 distributing

x%5E3%2B3x%5E2%2B2x-2184=0 subtracting 2184 from both sides

Now we can use a property of cubic equations.

IF the equation has an integer root, then the integer root MUST be a factor of 2184, the constant part of the equation.

So let's factor 2184:

Doing a quick prime factorization, the factors of 2184 that can be a possible root are ALL the positive/negative factor values (all the possible combinations of the prime factors):

1, 2, 4, 6, 7, 8, 12, 13, 21, 28, 36...2184

since 2184=2%2A2%2A2%2A3%2A7%2A13

So the integer root we are looking for must be somewhere on that list above!

Doing quick math, we can now see that 12*13*14=2184

Since we have verified that our x=12, now we just need to sum up the three integers.

12+13+14=39 final answer is 39 D