You can put this solution on YOUR website! Find four consecutive even integers such that twice the sum of the first and fourth is 124
1st=x
2nd=x+2
3rd=x+4
4th=x+6
.
so,
2[(x)+(x+6)]=124
2(2x+6)=124
4x+12=124
4x=124-12
4x=112
x=28
so,
1st =28
2nd=30
3rd=32
4th=34
(2)(28+34)=124
124=124