SOLUTION: Find two consecutive odd integers such that twice the greater is 17 more than the lesser. x x+2

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Question 228455: Find two consecutive odd integers such that twice the greater is 17 more than the lesser.
x
x+2
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct to start with x and x+2.
Let x= smaller odd number
x+2= larger odd number

Now, translate the sentence from English into math symbols.
". . . twice the greater is 17 more than the lesser."
2(x+2) = x+17
2x+4 = x + 17

Subtract x from each side:
2x-x+4= x-x + 17
x+4 = 17

Subtract 4 from each side:
x+4-4=17-4
x=13 Smaller
x+2= 15 Larger

Check:
twice the greater is 17 more than the lesser.
2*15= 13+17
It checks!!

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Seminole State College of Florida
Altamonte Springs Campus