SOLUTION: Find the largest of three consecutive odd integers such that the sum of the first two integers is five more than the third integer.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find the largest of three consecutive odd integers such that the sum of the first two integers is five more than the third integer.      Log On


   

Question 225301: Find the largest of three consecutive odd integers such that the sum of the first two integers is five more than the third integer.
Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
First integer: x
Second integer: x+2
Third integer: x+4
So, from our given statement:
%28x%2Bx%2B2%29=%28x%2B4%29%2B5
Combine like terms:
2x%2B2=x%2B9
Move the x over by subtracting it:
x%2B2=9
Subtract 2 from both sides:
x=7
So, that is our smallest number.
Our second integer is: x%2B2=7%2B2=9
The third integer is: x%2B4=7%2B4=-11