SOLUTION: Find three consecutive even integers whose sum is 36.

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Question 223001: Find three consecutive even integers whose sum is 36.
Answer by drj(1380) About Me  (Show Source):
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Find three consecutive even integers whose sum is 36.

Step 1. Let n be an even integer.

Step 2. Let n+2 and n+4 be the next two consecutive even integers.

Step 3. Then n+n+2+n+4=36 since the sum of these three even integers is 36.

Step 4. Solving yields the following steps

3n%2B6=36

Subtract 6 from both sides of the equation

3n-6=36-6

3n=30

Divide by 3 to both sides of the equation

3n%2F3=30%2F3

n=10 n%2B2=12 nad n%2B4=14. Not these three even integers add up to 36.

Step 5. ANSWER: The three consecutive even integers are 10, 12, and 14.


I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J