SOLUTION: simplify your answer. assume that no denominators are 0. show cancelling and factoring. y^2-49/z^2+z divided by y+7/ z

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: simplify your answer. assume that no denominators are 0. show cancelling and factoring. y^2-49/z^2+z divided by y+7/ z      Log On


   

Question 207932This question is from textbook algebra 1 an integrated approach
: simplify your answer. assume that no denominators are 0. show cancelling and factoring.
y^2-49/z^2+z divided by y+7/ z This question is from textbook algebra 1 an integrated approach

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
%28%28y%5E2-49%29%2F%28z%5E2%2Bz%29%29%2F%28%28y%2B7%29%2Fz%29
First we'll start by changing the division into multiplication by the reciprocal:
%28%28y%5E2-49%29%2F%28z%5E2%2Bz%29%29%2A%28z%2F%28y%2B7%29%29
Next we will factor each numerator and each denominator. We do this now before we multiply because it is easier now and because we can cancel (including "cross-cancel") common factors before we multiply making the rest of the simplification easier. The first numerator is a difference of squares %28a%5E2+-+b%5E2%29 and the first denominator has a GCF of "z":
%28%28%28y%2B7%29%28y-7%29%29%2F%28z%28z%2B1%29%29%29%2A%28z%2F%28y%2B7%29%29
Now we can cancel the common factors:

leaving:
%28y-7%29%2F%28z%2B1%29
This cannot be simplified further so this is the answer.