SOLUTION: sara has $1.45 in nickles and dimes. There are 18 in all. how many of many of each are there? Use the 5-step method and a table in solving this problem. (hint this problem is very

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: sara has $1.45 in nickles and dimes. There are 18 in all. how many of many of each are there? Use the 5-step method and a table in solving this problem. (hint this problem is very       Log On


   



Question 205398This question is from textbook algebra 1 an integrated approach
: sara has $1.45 in nickles and dimes. There are 18 in all. how many of many of each are there? Use the 5-step method and a table in solving this problem. (hint this problem is very similar to the try it exercise on page 205. use the answer to that question to help you determine the variables and organize your table.) i really hope u guys can help me i got the table all set up and the first part of this problem figured out i just didnt know how to solve it! thank you for your time !!!!!!!!!!!!!!!!!!! This question is from textbook algebra 1 an integrated approach

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
N+D=18
N=18-D
.05N+.10D=1.45
.05(18-D)+.10D=1.45
.90-.05D+.10D=1.45
.05D=1.45-.90
.05D=.55
D=.55/.05
D=11 DIMES.
N+11=18
N=18-11
N=7 NICKLES.
PROOF:
.05*7+.10*11=1.45
.35+110=1.45
1.45=1.45