SOLUTION: Find three consecutive odd integers such that 3 times the largest is 57 more than twice the smallest.
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Question 175728
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Find three consecutive odd integers such that 3 times the largest is 57 more than twice the smallest.
Answer by
Mathtut(3670)
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call our integers a, a+2, and a+4
:
3(a+4)=2a+57
:
3a+12=2a+57
:
a=45
:
:
integers are: