SOLUTION: Find three consecutive even integers such that the sum of the larger two integers is 54 more than the smallest integer.

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Question 175727: Find three consecutive even integers such that the sum of the larger two integers is 54 more than the smallest integer.
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
Call the first integer x. Then the next two can be represented by x+2 and x+4 (think about 2,4,6 as an example). Then the "sum of the larger two" would be (x+2) + (x+4) and "54 more than the smallest integer" would be x+54. So we have the equation
%28x%2B2%29%2B%28x%2B4%29=x%2B54
2x%2B6=x%2B54
Subtracting x from both sides and subtracting 6 from both sides, we get
x=48
Thus, the three consecutive even integers are 48, 50, and 52.