SOLUTION: Find 3 consecutive integers such that twice the least integer is 12 more than the greatest integer.

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Question 175273: Find 3 consecutive integers such that twice the least integer is 12 more than the greatest integer.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Least of 3 consecutive integers: x

Next consecutive integer: x+%2B+1

Greatest of 3 consecutive integers: x+%2B+2

Twice the least: 2x

Twelve more than the greatest: %28x+%2B+2%29+%2B+12+=+x+%2B+14

"is" means equals (unless you are Bill Clinton) so 2x+=+x+%2B+14

Solve for x and you have the smallest one, then count to find the other two.