SOLUTION: Hi I need your help. Three consecutive odd integers are such that the square of the third is 264 more than the square of the second. Find the three integers. I'm trying to understa

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hi I need your help. Three consecutive odd integers are such that the square of the third is 264 more than the square of the second. Find the three integers. I'm trying to understa      Log On


   

Question 146915: Hi I need your help. Three consecutive odd integers are such that the square of the third is 264 more than the square of the second. Find the three integers. I'm trying to understand how you would write this out to be able to work it. Thank you, Reuben
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let the integers be x, x+2, x+4
(x+4)^2=(x+2)^2+264
x^2+8x+16=x^2+4x+4+264
4x-252=0 subtract the right side from the left.
4x=252
x=63
63, 65, 67 are the integers.
.
Ed