Question 140973: The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width.
Answer by jojo14344(1513) (Show Source):
You can put this solution on YOUR website! First and formost Perimeter of rectangle(P)=2(Length+Width)---------- eqn 1.
But, there's a condition such being the Length 2 more than 3 times the Width.
Therefore, the Length =2+(3)(Width)
Going back eqn 1 and substituting the values:
600=2(2+3W+W)
600=2(2+4W)
600=4+8W
W=74.50
Solving for L by reversing eqn 1. becomes L=(P-2W)/2=(600-2*74.50)/2
L=225.50
Thank you,
Jojo
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