SOLUTION: find 2 consecutive odd integers whose sum is 65.

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Question 139232This question is from textbook
: find 2 consecutive odd integers whose sum is 65. This question is from textbook

Answer by solver91311(24713) About Me  (Show Source):
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No such integers exist. If you add two odd integers, then the sum must be even. Proof: The nth odd integer is 2n-1, and the mth odd integer is 2m-1, %282n-1%29%2B%282m-1%29=2n%2B2m-2 which is divisible by 2 and therefore even.

Now there are two consecutive integers that sum to 65, but one of them is even and the other one odd. Write back or re-post if that is what you really meant.